Answer with Step-by-step explanation:
We are given that displacement of wave

Where y in cm and t in sec.
a.Compare it with

Amplitude of wave=A
We get A=1.5
Amplitude=A=1.5 cm
b.k=0.68


Using

Wavelength of the wave=9.2 cm
c.Period=



The period of the wave=0.17 s
Speed of the wave=

Speed of the wave=54.1 cm/s