Answer:
Acceleration=a=24.9 m/s^2≅
Acceleration in g's:
Acceleration=24.9/9.8=2.54 g's
Step-by-step explanation:
Given:
Revolutions= 3.0 revolutions per second
Distance from the axis of spin=7.0 cm=0.07 m
Required:
Radial acceleration (in m/s^2 and in g’s) of the endolymph fluid=?
Solution:
Time for one revolution:
T=1/3 rev=0.333 sec
Distance= Speed*Time
Speed=Distance/Time
Distance=2πR
Acceleration in circular Path:
Acceleration=a=24.9 m/s^2≅
Acceleration in g's:
Acceleration=24.9/9.8=2.54 g's