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-5x + y = -2, -3x + 6y= -12. Solve each system by substitution

User MatFiz
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1 Answer

2 votes

Answer: x = 0, and y = -2

Explanation:

-5x + y = -2 .........(1)

-3x + 6y = -12 ......(2)

From equation (1)

-5x +y = -2 .........(1)

y = 5x - 2 .............(3)

Now substitute for y in equation (2)

-3x + 6 (5x -2 ) = -12

Make use of 6 to open the bracket ,we now have

-3x + 30x - 12 = -12

= 27x - 12 = -12

Collect the like terms

27x = -12 + 12

27x = 0

Divide through by 27 to get the value of x

x = 0/27

x = 0

To determine y, substitute for x in equation (3)

y = 5x - 2

y = 5(0) - 2

y = 0 - 2

y = -2

Check : Substitute for x and y in equation (1)

-5x + y = -2

-5(0) + (-2) = -2

0 -2 = -2

0 - 2 = -2

User Ifta
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