Length of segment of the hypotenuse adjacent to the shorter leg is 5 inches and the length of the altitude is 3 inches.
Explanation:
Step 1: Let the triangle be ΔABC with right angle at B. The altitude drawn from B intersects the hypotenuse AC at D. So 2 new right angled triangles are formed, ΔADB and ΔCDB.
Step 2: According to a theorem in similarity of triangles, when an altitude is drawn from any angle to the hypotenuse of a right triangle, the 2 newly formed triangles are similar to each other as well as to the bigger right triangle. So ΔABC ~ ΔADB ~ ΔCDB.
Step 3: Identify the corresponding sides and form an equation based on proportion. Let the length of the altitude be x. Considering ΔABC and ΔADB, AB/DB = AC/AB
⇒ 6/x = 12/6
⇒ 6/x = 2
⇒ x = 3 inches
Step 4: To find length of the hypotenuse adjacent to the shorter leg (side AB of 6 inches), consider ΔADB.
⇒
![AD^(2) + BD^(2) = AB^(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/6abpe12l9gutn4eyc5zeh4vk4t8yyvs3qw.png)
⇒
![AD^(2) =AB^(2) - BD^(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/xlexlyf46ebdtp0udx9pnwigadqi8zt04k.png)
⇒
![AD^(2) =6^(2) -3^(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/dl63g55tuj40xc8j8dcz4vkoxoh6wrbxa3.png)
⇒
![AD^(2) =36 - 9 = 25](https://img.qammunity.org/2021/formulas/mathematics/middle-school/41vzcwqsoupg4x6tcmxngti5r9t8o90ecp.png)
⇒
![AD = √(25)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/wxk6xxy50d7zwydiz9hez85djm17ar14o4.png)
⇒AD = 5 inches