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f(x) = sqrt (x-2), a = 2 (a) show that f is one-to-one. (b) Use Theorem 7 to find s f 21d9sad. (c) Calculate f 21sxd and state the domain and range of f 21. (d) Calculate s f 21d9sad from the formula in part (c) and check that it agrees with the result of part (b). (e) Sketch the graphs of f and f 21 on the same ax

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Answer:

21

Explanation:

User Zereges
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To show that f(x) = sqrt(x-2) is one-to-one, we need to prove that if f(a) = f(b), then a = b. Let's assume that f(a) = f(b), which gives us sqrt(a-2) = sqrt(b-2). Squaring both sides of the equation, we get a-2 = b-2, and therefore a = b. This shows that f(x) = sqrt(x-2) is one-to-one.

To show that the function f(x) = sqrt(x-2) is one-to-one, we need to prove that if f(a) = f(b), then a = b. Let's assume that f(a) = f(b), which gives us sqrt(a-2) = sqrt(b-2). Squaring both sides of the equation, we get a-2 = b-2, and therefore a = b. This shows that f(x) = sqrt(x-2) is one-to-one.

To find f(21), we substitute x = 21 into the function. f(21) = sqrt(21-2) = sqrt(19).

For f(21), the domain is the set of all real numbers greater than or equal to 2, and the range is the set of all real numbers greater than or equal to 0. So, the domain and range of f(21) are [2, ∞) and [0, ∞) respectively.

To calculate sqrt(21-2) using the formula from part (c), we substitute x = 21 into the function. sqrt(21-2) = sqrt(19). This agrees with the result from part (b).

To sketch the graphs of f(x) = sqrt(x-2) and f(21), we can plot the points on a coordinate plane using a suitable scale and connect them to form the graphs.

f(x) = sqrt (x-2), a = 2 (a) show that f is one-to-one. (b) Use Theorem 7 to find-example-1
User Joey Dalu
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