Answer:
photons are emitted per second in a
Watt microwave oven.
Step-by-step explanation:
The expression for the power is:-
![Power=(Energy)/(Time)](https://img.qammunity.org/2021/formulas/chemistry/college/7ptnffjte3lpznhqfcm8twh4iuvbxzci5u.png)
Also,
![E=n* (h* c)/(\lambda)](https://img.qammunity.org/2021/formulas/chemistry/college/rnkkemepp26dfp0pvjahxwi2cdampzi3py.png)
Where,
n = the number of photons
h = Plank's constant having value
![6.626* 10^(-34)\ Js](https://img.qammunity.org/2021/formulas/chemistry/college/qilm2blzqctdhq3r29e203n5vtvquze6su.png)
c = the speed of light having value
![3* 10^8\ m/s](https://img.qammunity.org/2021/formulas/chemistry/high-school/r6wk3ea3nlvbjfa6xqjl33qiabrr3ubziq.png)
= the wavelength of the light
So,
![Power=(n)/(Time)* (h* c)/(\lambda)](https://img.qammunity.org/2021/formulas/chemistry/college/gmji9e9oxu0202oj65uol3ajhd05sn3re2.png)
Thus, the expression for photons per second is:-
![(n)/(Time)=(Power* \lambda)/(h* c)](https://img.qammunity.org/2021/formulas/chemistry/college/4z3idog0o9ud4ip4xudysgev6d4mj51hiq.png)
Given that:-
Power = 10³ Watt
( 1 cm = 0.01 m)
[/tex]
So,
![Photon/sec=(10^(3)* 0.148)/(6.626* 10^(-34)* 3* 10^8)=7.45* 10^(26)](https://img.qammunity.org/2021/formulas/chemistry/college/sdn3mvgrkq4aheu9svzq1lukfhj55fwvs8.png)
photons are emitted per second in a
Watt microwave oven.