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Graph y > -1/3x+5

y > - (1)/( 3 ) x + 5


User Spunky
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1 Answer

6 votes

Step-by-step explanation:

The function is
y>-(1)/(3) x+5

To graph the function, let us find the x and y intercepts.

To find x-intercept, let us substitute y=0 in the function
y>-(1)/(3) x+5


\begin{aligned}0 &=-(1)/(3) x+5 \\-5 &=-(1)/(3) x \\x &=15\end{aligned}

Thus, the x-intercept is
(15,0)

To find the y-intercept, let us substitute x=0, we get,


\begin{aligned}&y=-(1)/(3)(0)+5\\&y=5\end{aligned}

Thus, the y-intercept is
(0,5)

The graph has no asymptotes.

To plot the points in the graph, we need to substitute the values for x in the function
y>-(1)/(3) x+5, to find the y-values.

The points are
(-2,5.667),(-1,5.333),(1,4.667),(2,4.333),(3,4). The image of the graph and table is attached below:

Graph y > -1/3x+5 y > - (1)/( 3 ) x + 5 ​-example-1
Graph y > -1/3x+5 y > - (1)/( 3 ) x + 5 ​-example-2
User Danieljames
by
8.5k points

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