Question

Nitrogen oxide racts with bromine to form nitrosyl bromide. A sample of 0.0655 mol NO with 0.0328 mol Br2 gives an equilibrium mixture containing 0.0389 mol NOBr. What is the composition of the equilibrum mixture?

2NO(g) + Br2(g) \leftrightarrow 2NOBr(g)

Answer 1

NO = 0.0265 mol

Br₂ = 0.0133 mol

NOBr = 0.0389 mol

Step-by-step explanation:

Let's consider the following reaction.

2 NO(g) + Br₂(g) ⇄ 2 NOBr(g)

We can find the composition at equilibrium using an ICE chart. Let x be an unknow amount.

2 NO(g) + Br₂(g) ⇄ 2 NOBr(g)

I 0.0655 0.0328 0

C -2x -x +2x

E 0.0655 - 2x 0.0328 - x 2x

At equilibrium, the mixture contains 0.0389 mol NOBr. Then,

0.0389 mol = 2x

x = 0.0195 mol

The composition of the equilibrium mixture is:

NO = 0.0655 - 2x = 0.0265 mol

Br₂ = 0.0328 - x = 0.0133 mol

NOBr = 0.0389 mol