Question

Cairo purchased a concert ticket for $30. The cost of the ticket was 5/6 the cost of his dinner. The cost of his hotel was 3 1/2 times as much as his ticket. How much did his dinner cost?

Answer 1

The cost of his dinner is $36.

Explanation:

Given:

Cost of ticket = $30

Cost of ticket is 5/6 the cost of his dinner.

Cost of his hotel was 3 1/2 times as much as his ticket.

Let the cost of dinner be 'x' dollars.

As per question:

Cost of ticket =
`(5)/(6)* x`

⇒
`30=(5x)/(6)`

Multiplying both sides by 6, we get:

`30* 6=(5x)/(6)* 6\\\\180=5x`

Dividing both sides by 5, we get:

`(180)/(5)=(5x)/(5)\\\\36=x\ or\\\\x=36`

Therefore, the cost of his dinner is $36.