Question

Eugenol is to be isolated using steam distillation. At 100 oC and 744.67 torr calculate the vapor pressure of pure eugenol at 100oC when 16.48% of the distillate collected is eugenol. The vapor pressure of water at 100oC is 760 torr. Put your answer in 5 significant figures.

Answer 1

Vapor pressure of Eugenol = 667.04torr

Step-by-step explanation:

By applying dalton's law of partial pressure;

at 100degree celsius, total pressure = 744.67torr

vapor pressure of water at 100 degree celsius = 760torr

mole fraction of eugenol = 0.1648

mole fraction of water = 1 - 0.1648 = 0.8352

Total pressure = vapor P(water) + vapor P( Eugenol)

for water; vapour pressure = mole fraction x total pressure

for eugenol; vapor pressure = mole fraction x total pressure

substituting into the above gives the vapor pressure of eugenol = 667.04torr