of
is
![6(1)/(7)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/4a0cswp1yunoe8jilmiyf6vi69vcjtv8o5.png)
Solution:
Given
of what number is
.
Let us first convert the mixed fraction into improper fraction.
![$2(2)/(3)=((2*3)+2)/(3)=(8)/(3)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/bldiufqbvsfoym5gc7pftm60ve9ybzcb6y.png)
![$6(1)/(7)=((6*7)+1)/(3)=(43)/(3)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/emh8q5w0ds8i543vknhph7zgnzoax1z0va.png)
Now, let us take the unknown number be x.
![$2(2)/(3)* x=6(1)/(7)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/kbrrb0en2k10eneyvs5za84w1q4dmt00zj.png)
![$(8)/(3)* x=(43)/(7)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/vyp224v43q3p799fxd3l7fr3owa0c1tr0u.png)
Do the cross multiplication.
![$ x=(43)/(7)*(3)/(8)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/mqm8rw86bi3129uencgf5n4wpfclev6yl8.png)
![$ x=(43*3)/(7*8)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/b6h0s4ttnewvwl0z8x1aanzens7pt71340.png)
![$ x=(129)/(56)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/k1vzpmt9py7q1pm2zatbrl5xx8nvbprz7i.png)
Now, again change the improper fraction into mixed fraction.
![$ x=2(17)/(56)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/28i7syi5v64kn3djux3ov1ha6oua1y9mhz.png)
Hence
of
is
.