Question

There are two parts to this question answer both parts. Pls write the expanded forms

part 1: write 49.02 in expanded form as a sum



part 2: rewrite the expanded form usin products of powers of 10

Answer 1

The number 49.02 in expanded form as a sum is 40 + 9 + 0.02; and rewritten using products of powers of 10 is 4 × 10¹ + 9 × 10° + 2 × 10⁻².

Step-by-step explanation:

Writing the number 49.02 in expanded form involves expressing each digit according to its place value. Therefore, we have:

40 (which is 4 tens, or 4 × 10)

9 (which is 9 ones, or 9 × 1)

0.02 (which is 2 hundredths, or 2 × 0.01)

In expanded form as a sum, 49.02 can be written as:

40 + 9 + 0.02

For part 2, when we rewrite the expanded form using products of powers of 10, it becomes:

4 × 10¹ (since 40 equals 4 times 10 to the first power)

9 × 10° (since 9 equals 9 times 10 to the zero power, because any number to the zero power is 1)

2 × 10⁻² (since 0.02 equals 2 times 10 to the negative second power)

So, 49.02 is equivalent to:

4 × 10¹ + 9 × 10° + 2 × 10⁻²

Answer 2

1. 49.02 = 40 + 9 + 0.0 + 0.02

2.
`49.02 = 4 * (10)^1 + 9 * (10)^0 +0 * (10^(-1) + 2 * (10)^(-2)`

Step-by-step explanation:

Part : 1

To write 49.02 as EXPANDED FORM

Now, by place value chart, we know

Ten Th. , Thousand, Hundreds, Tens , units DECIMAL, Tenth, Hundredth

Putting the value of decimal just below decimal ,we get:

Place value of 4 = 4 tens = 4 x 10 = 40

Place value of 9 = 9 ones = 9 x 1 = 9

Place value of 0 = 0 tenth = 0 / 10 = 0

Place value of 2 = 2 hundredth = 2 / 100 = 0.02

⇒ 49.02 = 40 + 9 + 0.0 + 0.02

Part : 2

Now, rewriting terms using powers of 10, we get:

40 = 4 x 10 = 4 x
`(10)^1`

9 = 9 x
`(10)^0`

0 = 0 x
`(10)^(-1)`

0.02 = 2 x
`(10)^(-2)`

⇒
`49.02 = 4 * (10)^1 + 9 * (10)^0 +0 * (10^(-1) + 2 * (10)^(-2)`