Question

A force of 2 Newtons will compress a spring from 1 meter (its natural length) to 0.8 meters. How much work is required to stretch the spring from 1.1 meters to 1.5 meters

Answer 1

The work required to stretch the spring from 1.1 meters to 1.5 meters is equal to 5.2 joules

Step-by-step explanation:

Given that,

Force acting on the spring, F = 2 N

The spring compresses from 1 meter (its natural length) to 0.8 meters

The force acting on the spring is given by :

`F=-kx`

`2=-k(0.8-1)`

k = 10 N/m

Let W is the work required to stretch the spring from 1.1 meters to 1.5 meters. It is given by :

`W=(1)/(2)k(x_2^2-x_1^2)`

`W=(1)/(2)* 10* (1.5^2-1.1^2)`

W = 5.2 Joules

So, the work required to stretch the spring from 1.1 meters to 1.5 meters is equal to 5.2 joules. Hence, this is the required solution.