Question

Now assume that the water is contained in a 0.1-kg aluminum pot (cAl = 900 J/kg-K) that is initially at 293 K just like the water. How much energy must be transferred into the pot-and-water system in order to raise its temperature to the boiling point of water?

Answer 1

In order to raise the temperature of the pot-and-water system to the boiling point of water, the total energy required is 843,700 J.

Step-by-step explanation:

In order to raise the temperature of the water in the pot to its boiling point, we need to calculate the amount of energy required to raise the temperature of both the pot and the water. The specific heat capacity of water is 4186 J/kg-K, while the specific heat capacity of aluminum is 900 J/kg-K. The mass of the pot is 0.1 kg and the mass of the water is 2.5 kg. The initial temperature of both the pot and the water is 293 K. The boiling point of water is 373 K.

To calculate the energy required to raise the temperature of the water, we use the formula Q = mcΔT, where Q is the energy transferred, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

For the water, the change in temperature is (373 K - 293 K) = 80 K.

Qwater = mwater * cwater * ΔTwater = (2.5 kg) * (4186 J/kg-K) * (80 K) = 836,500 J.

For the pot, the change in temperature is (373 K - 293 K) = 80 K.

Qpot = mpot * cpot * ΔTpot = (0.1 kg) * (900 J/kg-K) * (80 K) = 7,200 J.

So, to raise the temperature of the pot-and-water system to the boiling point of water, the total energy required is Qtotal = Qwater + Qpot = 836,500 J + 7,200 J = 843,700 J.