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You are tasked to specify the flash storage device in General Electric's Data Logger Unit used in the smart power grid. The DLU records data from 4 processors. Each processor generates 16 KB of data per
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You are tasked to specify the flash storage device in General Electric's Data Logger Unit used in the smart power grid. The DLU records data from 4 processors. Each processor generates 16 KB of data per second. Sought: What is the sufficient capacity for the DLU to record 3 day s worth of data?

User Sebastian Sebald
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Answer:

16.5888 GB

Step-by-step explanation:

The smart power grid operates 24/7; since we want to store up to 3 days worth of data and every day has 86400 seconds we need to store a total of 259200 seconds of data; we have four devices operating continuously during that time and each processor generates 16 KB of data per second, therefore, the total data in one second is 16*4 = 64KB/seg. To find the storage S we multiply the time of operation by the data collected in one second -> S = 259200 seg * 64KB/seg = 16588800 KB equivalent to 16.5888 GB of data in three days for all processors.

User Dariusz Krynicki
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