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A 53kg sled is on the snow with us=0.0888 what is the maximum static friction force on the sled

User Freerobots
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2 Answers

6 votes

Answer:

46.122

Step-by-step explanation:

User Jackson Lee
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6 votes

Answer: The maximum static friction force on the sled is 46.122 Newton

Step-by-step explanation:

Given Data

Mass of the sled = 53 kg

Coefficient static friction force (
\mu_(S)) = 0.0888 (No unit)

To find - the Maximum static friction force

The formula to find the Maximum static friction force
F_(S)^(\max ) is

Maximum static friction force
F_(S)^(\max ) = Product of coefficient of static friction force (
\mu_(S)) and normal force (η)


F_(S)^(\max ) =
\mu_(S) × η (Newton)

Formula to calculate the normal force (η) is

Normal force (η) = mass × acceleration due to gravity (Newton)

(where acceleration due to gravity has the constant value of 9.8 m/s²)

Normal force (η) = 53 × 9.8 (Newton)

Normal force (η) = 519.4 (Newton)

Maximum static friction force (
F_(S)^(\max )) =0.0888 × 519.4 (Newton)

Maximum static friction force (
F_(S)^(\max ) ) = 46.122 Newton

The maximum static friction force (
F_(S)^(\max ) ) is 46.122 Newton for the sled with mass 53 kg and coefficient of static friction force (η) 0.0888 (no unit).

User Eric Tjitra
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