Answer: The expression of the marginal cost of producing shoes at n would be :
![2n^{(-1)/(2)}+6n](https://img.qammunity.org/2021/formulas/mathematics/high-school/18pi099do8k38b6rtao7839wo3313wd8y8.png)
Explanation:
Given : The cost of producing n pair of shoes is given by
![C(n)=4n^{(1)/(2)}+3n^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/2z18rw32j1w9nk8gxy5q4nam0xe1k0fvmp.png)
Since , the marginal cost of producing shoes at n is the derivative of C at n.
Therefore , Marginal cost function =
![C'(n)=4 ((1)/(2)n^{(1)/(2)}-1)+3(2n)\ \ [\because\ (d\ x^m)/(dx)=mx^(m-1)]](https://img.qammunity.org/2021/formulas/mathematics/high-school/bk7xprxgveza7yz7fqu40ctc3fa3faio2w.png)
![=2n^{(-1)/(2)}+6n](https://img.qammunity.org/2021/formulas/mathematics/high-school/2x7lzzrikha4jt2s3nlldljtqrpljekmir.png)
Hence, the expression of the marginal cost of producing shoes at n would be :
![2n^{(-1)/(2)}+6n](https://img.qammunity.org/2021/formulas/mathematics/high-school/18pi099do8k38b6rtao7839wo3313wd8y8.png)