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A 53kg sled is on the snow with us=0.0888 what is the maximum static friction force on the sled

2 Answers

2 votes

Answer:

46.122 Newton

Step-by-step explanation:

User Switz
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The maximum static friction force on the sled is 46.122 Newton

Step-by-step explanation:

Given Data

Mass of the Sled = 53 kg

Coefficient static friction force (
\mu_(s)) = 0.0888 (No unit)

To find - the Maximum static friction force

The formula to find the Maximum static friction force is

Maximum static friction force = Product of coefficient of static friction force (
\mu_(s)) and normal force (η)


F_(S)^(max) =
\mu_(s) η (Newton)

Formula to calculate the normal force (η) is

Normal force (η) = mass × acceleration due to gravity (Newton)

(where acceleration due to gravity has the constant value of 9.8 m/s²)

Normal force (η) = 53 × 9.8 (Newton)

Normal force (η) = 519.4 (Newton)

Maximum static friction force (
F_(S)^(max) ) =0.0888 × 519.4 (Newton)

Maximum static friction force (
F_(S)^(max) ) = 46.122 Newton

The maximum static friction force (
F_(S)^(max) ) is 46.122 Newton for the sled with mass 53 kg and coefficient of static friction force (η) 0.0888 (no unit).

User MoFoLuWaSo
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