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4x^2 + 20 = 0; TAKING SQUARE ROOTS

1 Answer

5 votes

Answer:

x₁ = i√5

x₂ = -i√5

Explanation:

Let's solve the equation using square roots.

4X^2 + 20=0

x² + 5 = 0 (Dividing by 4 at both sides of the equation)

x² = -5 (Subtracting 5 at both sides of the equation)

√x² = √-5 (Square root to both sides of the equation, √-1 = i)

x = +/- i√5 ( (Roots of the solution)

x₁ = i√5

x₂ = -i√5

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