The electric potential energy of the point charges is directly proportional to the charge on the point charged particle and inversely proportional to the distance between the point charges.
Mathematically the general expression is
![U_p = (kq_p)/(r_p)](https://img.qammunity.org/2021/formulas/physics/college/6hxm664852j925hzjt7ss73kb7gwoi7j9s.png)
Here,
k = Coulomb's constant
= Charge
= Distance
From the aforementioned consideration we have to
![U_p \propto (1)/(r_p)](https://img.qammunity.org/2021/formulas/physics/college/zjr8j8cj6bxsm4pm5bpybiy9pny10d4rw2.png)
Between two loading states (final and initial) the expression would become
![(U_p)_1 (r_p)_1 = (U_p)_2 (r_p)_2](https://img.qammunity.org/2021/formulas/physics/college/4h3ardwj9h53uwbbkxmjmrg1vllnhll93r.png)
If the distance between the two points is the double
we can now write the expression as
![(U_p)_1 r_p = (U_p)_2 (2r_p)](https://img.qammunity.org/2021/formulas/physics/college/bkkvp1fov7p3wayns5khs9qpf91z16sh66.png)
![(U_p)_2 = ((U_p)_1)/(2)](https://img.qammunity.org/2021/formulas/physics/college/gdjuodr1u99la9c5nslzi6ucxagd5syafj.png)
Therefore te potential energy when the distance between the point charge is double, is U/2.
Therefore the correct answer is B.