Question

Passing through the points (6,8) & (9,6)

Answer 1

Slope-intercept form: y = mx + b [m is the slope, b is the y-intercept or the y value when x = 0 ---> (0, y) or the point where the line crosses through the y-axis]

To find the slope, use the slope formula (m):

`m=(y_2-y_1)/(x_2-x_1)` and plug in the two points

(6, 8) = (x₁, y₁)

(9, 6) = (x₂, y₂)

`m=(y_2-y_1)/(x_2-x_1)`

`m=(6-8)/(9-6)`

`m=(-2)/(3)` Now that you found the slope, plug it into the equation

y = mx + b

`y=-(2)/(3) x+b` To find b, plug in one of the points, I will use (6, 8)

`8=-(2)/(3) (6)+b`

8 = -4 + b Add 4 on both sides

12 = b Now plug in b into the equation

`y=-(2)/(3) x+12`