The x-intercepts are

The y-intercepts are

Step-by-step explanation:
The relation is

To find the x-intercept, let us substitute
in the equation
, we get,

Thus, the x-intercepts are

To find the y-intercept, let us substitute
in the equation
, we get,

let us switch sides and solving, we get,

Taking square root,
and

Thus, the y-intercepts are
