Question

A 70kg person jumps off a staircase. They are going 5 m/s just before they hit the ground. How high up where they.

Answer 1

1.25m

Explanation:

v=u+gt

5=0+10t

5=10t

t=0.5s

s=ut+1/2gt^2

=0+(0.5×10×(0.5)^2)

=1.25m

Answer 2

0.02 seconds

Step-by-step explanation: A 70kg man jumps 1.00 meters down onto a concrete walkway. His downward motion stops in 0.02 seconds.