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An electric current of 0.520A flows for 411 milliseconds. Calculate the amount of electric charge transported. Be sure your answer has the correct unit symbol and the correct number of significant figures.

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The electric current intensity (I) is the amount of electricity or electric charge (Q) that circulates through a circuit in the unit of time (t). Mathematically it can be described as


I = (Q)/(t) \rightarrow Q= It

Our values are,


I = 0.520A


t = 411ms = 411*10^(-3)s

Replacing we have that the charge is


Q = (0.520A)( 411*10^(-3)s )


Q = 0.21372C

Therefore the amount of electric charge transported is 0.2137 Coulombs

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