Question

The spinner shown is divided into congruent sections that are labeled from 1 through 7.If the spinner is spun one time, what is the probability of the arrow not landing on a section labeled with an odd number?

Answer 1

The probability of the spinner not landing on a section labeled with an odd number is 3/7, which corresponds to the three even-numbered sections (2, 4, 6) out of the seven total sections.

Step-by-step explanation:

The probability of the arrow not landing on a section labeled with an odd number can be calculated by identifying the number of sections with even numbers and dividing that by the total number of sections on the spinner. Since the spinner is divided into sections labeled from 1 through 7, there are three even-numbered sections (2, 4, 6) and four odd-numbered sections (1, 3, 5, 7). So the probability of not landing on an odd number is the probability of landing on an even number.

Probability of not landing on an odd number = Number of sections with even numbers / Total number of sections = 3 (even-numbered sections) / 7 (total sections) = 3/7.

This is the probability of the spinner landing on an even number since only even numbers are not odd in this range of labels.

Answer 2

The probability of the arrow not landing on a section labeled with an odd number is 3/7

Step-by-step explanation:

Total number of congruent sections is 7

Total number of congruent sections with odd numbers(1,3,5,7) is 4.

The probability of the spinner landing on a section labelled with an odd number is 4/7.

The probability of the spinner landing on a section which is not labelled with an odd number is 1-4/7 = 3/7 ( Because the sum of probability of the spinner landing on any number is 1)

Hence the answer is 3/7