Question is incomplete , complete question is:
One supply is a 30% solution, and the other supply is a 60% solution. On one occasion, ACC needs to manufacture 50% solution of
. Which could be the amounts they use of each to make 100 grams of a 50% solution of
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Answer:
33.37 grams of 30% phosphoric acid solution and 66.67 grams of 60% phosphoric acid solution will used to make 100 grams of 50% phosphoric acid solution.
Step-by-step explanation:
Let the amount of 30% phosphoric acid solution be x and 60% phosphoric acid solution be y.
Amount of 50% phosphoric acid solution to be made= 100 g
x + y = 100 g..[1]
Amount of phosphoric acid in x grams solution = 30% of x = 0.3x
Amount of phosphoric acid in y grams solution = 60% of y = 0.6y
Amount of phosphoric acid in 100 grams of 50% solution = 50% of 100 = 50 g
0.3x +0.6y = 50 g..[2]
Solving [1] and [2] we get :
y = 66.67 g
x = 33.33 g
33.37 grams of 30% phosphoric acid solution and 66.67 grams of 60% phosphoric acid solution will used to make 100 grams of 50% phosphoric acid solution.