Question

Name

WS #69
WS: 6.1b - Evaluating Functions
quations in function notation
Standard H.2A.5.C3: I can solve equations in function no
d. g(5)
Directions: Solve each function for the requested value.
1. Let g(x) = x2 - 5x + 2. Find the following:
a. g(-1)
b. g(-2)
c. g(0)

Answer 1

A) g(-1) = 8

B) g(-2) = 16

C) g(0) = 2

Explanation:

The given equation is
`g(x) = x^(2) + 5x + 2`

A) Substituting the value of x = -1 in the given equation we get,

`g(-1) = (-1)^(2) - \left \{5*(-1) \right \} + 2`

= 1 + 5 + 2

= 8

B) Substituting the value of x = -2 in the given equation we get,

`g(-2) = (-2)^(2) - \left \{5*(-2) \right \} + 2`

= 4 + 10 + 2

= 16

C) Substituting the value of x = 0 in the given equation we get,

`g(0) = (0)^(2) - \left \{5*(0) \right \} + 2`

= 0 - 0 + 2

= 2