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Why is the Area for my shape not correct and can you explain why?

Why is the Area for my shape not correct and can you explain why?-example-1
User Adrbtk
by
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1 Answer

5 votes


\bold{\huge{\underline{ Solution }}}

Here, We have given

  • 2 squares , In which 1 square is enclosed within the another square and it arranged in a form that it forms 4 right angled triangle
  • The height and base of the given right angled triangles are 6 and 3 each.

We know that,

Area of triangle


{\sf{=}}{\sf{(1)/(2)}}{\sf{ {*} base {*} height }}

Subsitute the required values,


{\sf{=}}{\sf{(1)/(2)}}{\sf{ {*} 3 {*} 6}}


\sf{ = 3 {*} 3 }


\bold{ = 9 }

Therefore,

Area covered by 4 right angled triangles


\sf{ = 4 {*} 9 }


\bold{ = 36}

Now,

We have to find the area of the big square

  • The length of the side of the big square

  • \sf{ = 6 + 3 = 9 }

We know that,

Area of square


\sf{ = Side {*} Side }

Subsitute the required values,


\sf{ = 9 {*} 9 }


\bold{ = 81 }

Therefore,

The total area of shaded region

= Area of big square - Area covered by 4 right angled triangle


\sf{ = 81 - 36 }


\bold{ = 45 }

Hence, The total area of shaded region is 45 .

Part 2 :-

Here,

We have to find the area of non shaded region

According to the question

  • Hypotenuse = The length of square

Let the hypotenuse of the given right angled triangle be x

Therefore,

By using Pythagoras theorem,

  • This theorem states that the sum of the squares of the base and perpendicular height is equal to the square of hypotenuse.

That is,


\sf{ (Perpendicular)^(2) + (Base)^(2) = (Hypotenuse)^(2) }

Subsitute the required values


\sf{ (6)^(2) + (3)^(2) = (x)^(2) }


\sf{ 36 + 9 = (x)^(2) }


\sf{ x = √(45)}


\bold{ x = 6.7 }

That means,

  • The length of the small square = 6.7

We know that ,

Area of square


\sf{ = Side {*} Side }

Subsitute the required values,


\sf{ = 6.7 {*} 6.7 }


\bold{ = 44.89 \:\: or \:\: 44.9 }

Therefore ,

Area of non shaded region

= Area of big square - Area of small square


\sf{ = 81 - 44.9 }


\bold{ = 36.1 }

Hence, The total area of non shaded region is 36.1 or 36 (approx) .

Part 3 :-

Here, we have to

  • find the total area of the figure

Therefore,

The total area of the figure

= Non shaded region + Shaded region


\sf{= 36 + 45 }


\bold{= 81}

Hence, The total area of the given figure is 81 .

User Yousha Arif
by
5.8k points