Answer:
5 a) Number of groups of 20 that can be formed
= 25C20
\small = \frac{25!}{5!*20!}
= 53130
b) Number of different meals possible = 2*7*3 = 42
Explanation:
5 a) Number of groups of 20 that can be formed
= 25C20
\small = \frac{25!}{5!*20!}
= 53130
b) Number of different meals possible = 2*7*3 = 42