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Find z such that the proportion of observations that are less than z in a standard normal distribution is 0.36 . (Enter your answer rounded to two decimal places.)

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Answer:

-0.36

Explanation:

For any given standard normal distribution, the value of the z-score at the 36th percentile can be found by simple observation of a z-score table.

At the 36th percentile, a normal distribution has a z-score of roughly -0.36.

Therefore -0.36 is the value of z such that the proportion of observations that are less than z is 0.36 .

User Mark Horgan
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