Question

Which is the equation of the line with slope 3 that contains point (-1,5)?

y-1 = 3(x + 5)
y - 1 = 3(x - 5)
y - 5= 3(x - 1)
y - 5= 3(x + 1)

Answer 1

D

`y-5=3(x+1)`

Explanation:

We can see that the question is asking for the Point-Slope Form;

`y-y_(1) =m(x-x_(1))`

The points go into the equation for
`y_(1)` and
`x_(1)`

`y-5=m[x-(-1)]`

M would be the slope;

`y-5=3[x-(-1)]`

Which basically is:

`y-5=3(x+1)`

Answer 2

the answer is y-5=3(x+1)