Question

2Na3N3 -> 2Na + 3N2

if 0.58 mol if NaN3 reacts, what mass of nitrogen would result

Answer 1

Mass = 24.36 g of N₂

Step-by-step explanation:

The balance chemical equation for the decomposition of NaNO₃ is as follow;

2 NaN₃ → 2 Na + 3 N₂

Step 1: Find moles of N₂ as;

According to equation,

2 moles of NaNO₃ produces = 3 moles of N₂

So,

0.58 moles of NaNO₃ will produce = X moles of N₂

Solving for X,

X = 3 mol × 0.58 mol / 2 mol

X = 0.87 mol of N₂

Step 2: Calculate mass of N₂ as,

Mass = Moles × M.Mass

Mass = 0.87 mol × 28.01 g/mol

Mass = 24.36 g of N₂