Answer:
![15.2+2w\leq 28](https://img.qammunity.org/2021/formulas/mathematics/high-school/ybay8if4dm99w7yqgwvvv29yqwd8g3di8g.png)
Explanation:
Let w represent width of the rope-off section.
We have been given that a manager needs to rope off a rectangular section for a private party the length of the section must be 7.6 m the manager can use no more than 28 m of the rope.
We will use perimeter of rectangle formula to solve our given problem. We know that perimeter of a rectangle is equal to 2 times the sum of length and width.
![\text{Perimeter}=2l+2w](https://img.qammunity.org/2021/formulas/mathematics/high-school/gnsy1on06eak7dultmxn41hehbhifuzxkp.png)
Upon substituting our given values, we will get:
![\text{Perimeter}=2(7.6)+2w\\\\\text{Perimeter}=15.2+2w](https://img.qammunity.org/2021/formulas/mathematics/high-school/dj2u6zx9h6p0fw1ymnelcmmr2zt9bxpvmu.png)
Since the manager can use no more than 28 m of the rope, so perimeter of rope-off section should be less than or equal to 28 meters.
We can represent this information in an inequality as:
![15.2+2w\leq 28](https://img.qammunity.org/2021/formulas/mathematics/high-school/ybay8if4dm99w7yqgwvvv29yqwd8g3di8g.png)
Therefore, our required inequality would be
.
Let us find width as:
![15.2-15.2+2w\leq 28-15.2](https://img.qammunity.org/2021/formulas/mathematics/high-school/3odrz13yox86poir7pxnpmm0dn4ho1yeod.png)
![2w\leq 12.8](https://img.qammunity.org/2021/formulas/mathematics/high-school/as2gx2jrrkb4383bnel5x0wlcob321hhbe.png)
![(2w)/(2)\leq (12.8)/(2)\\\\w\leq6.4](https://img.qammunity.org/2021/formulas/mathematics/high-school/gei9ny6d2xmufeybtnxh9iy7e5iydqpaof.png)
Therefore, the width of the rope-off section should be less than or equal to 6.4 meters.