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A manager needs to rope off a rectangular section for a private party the length of the section must be 7.6 m the manager can use no more than 28 m of the rope What inequality Could it is to find the possible width, w, of the rope-off section

2 Answers

3 votes

Answer:

Explanation:

Explanation:

Let w represent width of the rope-off section.

We have been given that a manager needs to rope off a rectangular section for a private party the length of the section must be 7.6 m the manager can use no more than 28 m of the rope.

We will use perimeter of rectangle formula to solve our given problem. We know that perimeter of a rectangle is equal to 2 times the sum of length and width.

Upon substituting our given values, we will get:

Since the manager can use no more than 28 m of the rope, so perimeter of rope-off section should be less than or equal to 28 meters.

We can represent this information in an inequality as:

Therefore, our required inequality would be .

Let us find width as:

User Madz
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6 votes

Answer:


15.2+2w\leq 28

Explanation:

Let w represent width of the rope-off section.

We have been given that a manager needs to rope off a rectangular section for a private party the length of the section must be 7.6 m the manager can use no more than 28 m of the rope.

We will use perimeter of rectangle formula to solve our given problem. We know that perimeter of a rectangle is equal to 2 times the sum of length and width.


\text{Perimeter}=2l+2w

Upon substituting our given values, we will get:


\text{Perimeter}=2(7.6)+2w\\\\\text{Perimeter}=15.2+2w

Since the manager can use no more than 28 m of the rope, so perimeter of rope-off section should be less than or equal to 28 meters.

We can represent this information in an inequality as:


15.2+2w\leq 28

Therefore, our required inequality would be
15.2+2w\leq 28.

Let us find width as:


15.2-15.2+2w\leq 28-15.2


2w\leq 12.8


(2w)/(2)\leq (12.8)/(2)\\\\w\leq6.4

Therefore, the width of the rope-off section should be less than or equal to 6.4 meters.

User Darcara
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