Question

Calculati volumul ocupat in conditii normale de temperatura si presiune de: a)14,2 kg Cl2; b)15,055×10²³ molecule Cl2 Va rogggggggg îmi trebuieeeeee urgentttt

Answer 1

a) 4480L

b) 56L

Step-by-step explanation:

To answer this question you need to know that Cl2 molecular weight is 71 g/mol and gas volume at NTP is 22.4 L/mol.

a) 14.2 kg of Cl2 in moles will be: 14.2 kg * (1000g/kg) / ( 71g/mol)= 200 mol

The volume of 200 mol of gas in NTP will be: 200 mol * 22.4L/mol= 4480L

b) every mol is made of 6.02 * 10²³ molecules. Then the volume of the gas will be: (15,055×10²³ molecule) / (6.02 * 10²³ molecules/mol) * 22.4 L/mol= 56L