Question

The area of the squared garden is 625 sq. m, what is its perimeter ? (Ans: 100 m)​

Answer 1

Answer: Area of square = a*a(where a is length of one side) Putting value a x a=625 cm2 a= 25 Perimeter will be 4 x a 4 x 25 = 100 cm

Explanation:

Answer 2

`\sf\huge\underline{Given:-}`

Area of the square field
`\sf{= 625 m^2}`

`\sf\huge\underline{To\: Find:-}`

`\rightarrow` Perimeter of the square garden.

`\sf\huge\underline{Formula \:Used:-}`

Area of square
`\sf{= side^2}`

Perimeter of square
`\sf{= 4×side}`

`\sf\huge\underline{Solution:-}`

As we know,

`\rightarrow` Area of square
`\sf{= side^2}`(putting the given value of area)

`\rightarrow`
`\sf{Side^2}`
`\sf{= 625}`

`\rightarrow`
`\sf{Side}`
`\sf{= √(625)}`

`\rightarrow`
`\sf{Side}`
`\sf{= 25cm}`

So, From here we got the side of the square garden that is, 25cm.

Now,

`\rightarrow`Perimeter of square
`\sf{= 4×side}`(Putting the value of side)

`\rightarrow` Perimeter of square
`\sf{= 4×25}`

`\rightarrow`Perimeter of square
`\sf{= 100cm}`

Therefore, perimeter of the square garden = 100cm.