Question

If V1 = 5,000 cc and T1 = 500 K, and T2 = 77 K, then what is V2?​

Answer 1

For the given problem, V2= 0.77 liter or 770 cc.

Step-by-step explanation:

The given data,

V1= 5,000 cc.

T1= 500 K.

T2 = 77K.

We have to calculate V2.

According to Charles law,

`(V1)/(T1)= (V2)/(T2) .`

Before applying let us convert the cc into liter.

1 liter = 1000 cc.

⇒5000 cc= 5 liter.

Let us substitute the values in the formula,

`(5)/(500)= (V2)/(77) .`

V2=
`((5)(77))/(500)`.

V2=
`(385)/(500)`.

V2= 0.77 liter.

In cc, V2= 770 cc.