Answer:
pH = 7.45
Step-by-step explanation:
The equilibrium that takes place in the buffer system is:
- CO₂ + H₂O ↔ H₂CO₃ ↔ H⁺ + HCO₃⁻
- [CO₂] = [H₂CO₃] + [HCO₃⁻]
We first calculate [H₂CO₃]:
- [H₂CO₃] = [CO₂] - [HCO₃⁻]
- [H₂CO₃] = 25.6 mM - 24.5 mM = 1.1 mM
The pH of the buffer according to the Henderson-Hasselbach equation would be:
- pH = pKa + log [HCO₃⁻]/[H₂CO₃]