Question

Given a normal distribution of scores with µ = 85 and σ = 17.5, what raw score lies at the upper boundary of the interval that includes scores within one standard deviation of the mean?

Answer 1

x = 102.5

Step-by-step explanation:

given,

mean of the normal distribution curve, µ = 85

standard deviation, σ = 17.5

z -score = 1

now, using formula of z-score

`Z = (x-\mu)/(\sigma)`

`1 = (x-85)/(17.5)`

x - 85 = 17.5

x = 17.5 +85

x = 102.5

hence, the upper bound value for the 1 standard deviation is equal to 102.5.