Question

Given a fixed amount of gas held at constant pressure, calculate the volume (in L) it would occupy if a 3.50 L sample were cooled from 90.0oC to 30.0oC.

Answer 1

The final volume of a gas originally occupying 3.50 L at 90.0°C when cooled to 30.0°C at constant pressure is 2.85 liters according to Charles's Law.

Step-by-step explanation:

The volume of a gas at constant pressure is directly proportional to its temperature in Kelvin, according to Charles's Law. To find the new volume (V2) when the temperature changes from 90.0°C to 30.0°C for a 3.50 L sample, we first convert the temperatures to Kelvin:

• T1 = 90.0°C + 273.15 = 363.15 K
• T2 = 30.0°C + 273.15 = 303.15 K

We then use the formula derived from Charles's Law: V1/T1 = V2/T2, where V1 is the initial volume and V1 is the final volume.

Solving for V2 gives us:

V2 = V1 × (T2/T1)

V2 = 3.50 L × (303.15 K / 363.15 K) = 2.85 L

So, at 30.0°C, the gas would occupy a volume of 2.85 liters.