192k views
5 votes
The magnitude of the resultant force is to be 200 N, directed along the positive ݒaxis. Determine the magnitude of the force Find the angle θ.

User Desiato
by
5.5k points

1 Answer

5 votes

Answer: F = 776.18N θ = 29.41°

Question:

The magnitude of the resultant force is to be 200 N, directed along the positive y-axis. Determine the magnitude of the force F Find the angle θ.

Attached is the image.

Step-by-step explanation:

To solve this question we need to resolve the forces to the x and y axis.

For the x axis;

Fcosθ = 700cos15....1

For the y axis;

200 = Fsinθ - 700sin15

Fsinθ = 200 + 700sin15 ...2

Dividing equation 2 by 1

Fsinθ/Fcosθ = (200 + 700sin15)/700cos15

Tanθ = (200 + 700sin15)/700cos15

θ = Taninverse(200 + 700sin15)/700cos15)

θ = 29.41°

From equation 1;

F = 700cos15/cosθ

F = 700cos15/cos29.41

F = 776.18N

The magnitude of the resultant force is to be 200 N, directed along the positive ݒaxis-example-1
User Ilya Zakharevich
by
5.6k points