Answer:
2Pp : 2pp ~ 1:1
Step-by-step explanation:
This is a monohybrid cross involving a single gene coding for flower colour in pea plant. The purple allele (P) is dominant over the white allele (p).
A heterozygous parent will possess Pp genotype and be phenotypically purple since P allele will be expressed over p. A white-flowered parent will possess a homozygous recessive genotype (pp) since the recessive trait will only be expressed in a homozygous state.
In a cross between Pp and pp (see attached image), four possible offsprings will be produced with two (2) having a Pp genotype and the other two (2), pp genotype. Hence, the genotypic ratio will be 2Pp:2pp equivalent to 1:1.