89.9k views
5 votes
Find the average value of f(x)=e2x over the interval [2, 4].

a. 1463.18

b. 731.59

c. 1517.78

d. 23.60

User Lope
by
8.2k points

1 Answer

5 votes

Option B is the correct answer.

Explanation:

We need to find average value of
e^(2x) in [2,4]

Area of
e^(2x) in [2,4] is given by


\int_(2)^(4)e^(2x)dx=(1)/(2)* \left [ e^(2x)\right ]^4_2\\\\\int_(2)^(4)e^(2x)dx=(1)/(2)*(e^8-e^4)=1463.18

Area of
e^(2x) in [2,4] = 1463.18

Difference = 4 - 2 = 2

Average value = Area of
e^(2x) in [2,4] ÷ Difference

Average value = 1463.18 ÷ 2

Average value = 731.59

Option B is the correct answer.

User Chris Midgley
by
7.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories