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For f(x)=1-x/1+x and g(x)=x/1-x, find the simplified form for f[g(x)] and state the domain

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Answer:

f(g(x))=1-2x

domain is set of all x values except 1

Explanation:


f(x)=(1-x)/(1+x) \\g(x)=(x)/(1-x)

we use composition of function f(g(x))

Plug in g(x) inside f(x)


f(g(x))= f((x)/(1-x))\\f(g(x))=(1-(x)/(1-x))/(1+(x)/(1-x)) \\\\f(g(x))=((1-x-x)/(1-x))/((1-x+x)/(1-x)) \\\\\\f(g(x))=((1-2x)/(1-x))/((1)/(1-x)) \\\\\\\\f(g(x))=1-2x

Domain is the set of x values for which the function is defined

for domain set 1-x=0

x=1

domain is set of all x values except 1

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