Question

At a distance of 0.186 cmcm from a large uniform sheet of charge, the electric field is 490 N/CN/C . What is the electric field 1.35 cmcm from the sheet?

Answer 1

`E=490 N/C`

Step-by-step explanation:

We are given that

At distance 0.186 cm

The electric field,E=490 N/C

We have to find the electric filed at distance 1.35 cm from the sheet.

We know that

Electric field due to large sheet ,E=
`(\sigma)/(2\epsilon_0)`

Where
`\sigma`=Surface charge density

`\epsilon_0=8.85* 10^}{-12}C^2/Nm^2`

Electric filed of sheet does not depend on distance.It is constant.

Electric filed at distance 0.186 cm=490 N/C

Therefore, the electric filed at distance 1.35 cm is also 490 N/C.

Hence, at distance 1.35 cm , the electric filed
`E=490 N/C`