The question is incomplete, here is the complete question:
If you performed a combustion reaction of 2-ethyl-1-methylpropene, what products would you expect to be present?
Answer: The products of the combustion of 2-ethyl-1-methylpropene are carbon dioxide and water.
Step-by-step explanation:
Combustion reaction is defined as the reaction in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide gas and water molecule.
![\text{Hydrocarbon}+O_2\rightarrow CO_2+H_2O](https://img.qammunity.org/2021/formulas/chemistry/college/27ypk53mnshzxk2ua8gnfokhr55zgt48oh.png)
We are given a chemical compound, which is 2-ethyl-1-methylpropene. The chemical formula of this compound is
![C_6H_(13)](https://img.qammunity.org/2021/formulas/chemistry/college/9jr0gwy23yp5n7p64107nbp2eskd6jf5jb.png)
The chemical equation for the combustion of 2-ethyl-1-methylpropene follows:
![4C_6H_(13)+37O_2\rightarrow 24CO_2+26H_2O](https://img.qammunity.org/2021/formulas/chemistry/college/x9geqzxki2mpx0zohu0pjaehvatfnlmbs0.png)
By Stoichiometry of the reaction:
4 moles of 2-ethyl-1-methylpropene reacts with 37 moles of oxygen gas to produce 24 moles of carbon dioxide and 26 moles of water
Hence, the products of the combustion of 2-ethyl-1-methylpropene are carbon dioxide and water.