Question

An electric field of intensity 4.25 kN/C is applied along the x-axis. Calculate the electric flux through a rectangular plane 0.350 m wide and 0.700 m long if the following conditions are true.

Answer 1

Electric flux will be equal to
`1041.25Nm^2/C`

Step-by-step explanation:

We have given electric field
`E=4.25KN/C=4.25* 10^3N/C=4250N/C`

Sides of rectangle is given as 0.350 m wide and 0.700 m long

So length of rectangle l = 0.7 m and width w = 0.35 m

So area of rectangle
`A=0.7* 0.35=0.245m^2`

It is given that electric field is along the x axis

So angle between plane and electric filed
`\Theta =0^(\circ)`

So electric flux will be equal to
`\Phi =EAcos\Theta =4250* 0.245* cos0^(\circ)=1041.25Nm^2/C`