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Find parametric equations and symmetric equations for the line. (Use the parameter t.) The line through (3, 1, 0) and perpendicular to both i + j and j + k

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Answer with Step-by-step explanation:

We are given that a point (3,1,0)

Two vectors are

A=<1,1,0>

B=<0,1,1>


A* B=\begin{vmatrix}i&amp;j&amp;k\\1&amp;1&amp;0\\0&amp;1&amp;1\end{vmatrix}


A* B=i-j+k

Let v
=A* B=i-j+k


v=<a,b,c>=<1,-1,1>


r_0=<x_0,y_0,z_0>=<3,1,0>


r=r_0+vt

Substitute the values then we get


r=<3,1,0>+t<1,-1,1>


r=<3+t,1-t,t>

The parametric equation of the line


x=x_0+at,y=y_0+bt,z=z_0+ct

Using the formula

The parametric equation of the line which is passing through the point (3,1,0) and perpendicular to both i+j and j+k is given by


x=3+t,y=1-t,z=t

The symmetric equation of the line is given by


(x-x_0)/(a)=(y-y_0)/(b)=(z-z_0)/(c)

Using the formula

The symmetric equation of the line which is passing through the point (3,1,0) and perpendicular to both i+j and j+k is given by


(x-3)/(1)=(y-1)/(-1)=z

User Kelly Adams
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