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A brass plug is to be placed in a ring made of iron. At 20 C, the diameter of the plug is 8.723 cm and that of the inside of the ring is 8.710 cm . They must both be brought to what common temperature in order to fit? What if the plug were iron and the ring brass?

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Answer:It started at 20°C, the bras and the iron must b cooled at -150°C.

Step-by-step explanation:

The formular for linear expansion is given by:

L = Lo + Lo&◇T

Where L = linear dimensions)diameter) after temperature change.

Lo=Original linear dimension

&= Coefficient of thermal expansion for the material.

◇T=Change in temperature.

At some temperature,L(brass)=L(iron)

Lo + Lo&◇T = Lo + Lo&◇T

8.753cm + 8.753cm×(8.7×10^-6C^-1)×◇T=8.753cm+ 8.753cm ×(12.0×10^-6C^-1)×◇T

8.753+(1.636×10^-4)◇T= 8.753+(1.049×10^-4C^-1)◇T

5.87 × 10^-5◇T= 0.010

◇T= 0.010/(5.87×10^-5)

◇T= 170°C

◇T=T1-T2

T= (20 - 170)°C

T= -150°C

User Ayyaz Zafar
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