Answer:
The work done will be 14,700 Nm.
Step-by-step explanation:
The standard formula to evaluate work done when the force and distance are given is,
![$W=F * d$](https://img.qammunity.org/2021/formulas/biology/middle-school/abtbsxb85dx06a6flc84gkbqmjy88wbgfs.png)
According to the question, the force applied and distance covered by the object is given as,
![F=700 N](https://img.qammunity.org/2021/formulas/biology/middle-school/7pk2sjmjiwpbb13aekqpghismriufi2da6.png)
![d=21 m](https://img.qammunity.org/2021/formulas/biology/middle-school/e8nifgvrhcx664ul26x0ffbki7rirba4c6.png)
Now putting all the values in the standard formula of work done, we get;
![W=700 * 21](https://img.qammunity.org/2021/formulas/biology/middle-school/zco6z7s97uweo9br7tomo92qgok8qlnh6o.png)
![W=14,700 \mathrm{Nm}](https://img.qammunity.org/2021/formulas/biology/middle-school/fdnjlcp2t4d4piq9la8hpwb5ztietxfkqp.png)
Hence the work done by the object through the force is 14,700 Nm.