Question

A piano wire with mass 2.60g and length 84.0 cm is stretched with a tension of 25.0 N. A wave with frequency 120.0 Hz and amplitude 1.6 mm travels along the wire. Calculate the average power carried by the wave. What is the average power if the wave amplitude is halved?

Answer 1

Power will be 0.2023 watt

And when amplitude is halved then power will be 0.0505 watt

Step-by-step explanation:

We have given mass of the Piano wire m = 2.60 gram = 0.0026 kg

Length of wire l = 84 cm = 0.84 m

So mass density
`\mu =(m)/(l)=(0.0026)/(0.84)=0.0031kg/m`

Tension in the wire T = 25 N

Frequency f = 120 Hz

So angular frequency
`\omega =2\pi f=2* 3.14* 120=753.6rad/sec`

And amplitude A = 1.6 mm = 0.0016 m

We have to find the generated power

Power is given by
`P=(1)/(2)√(\mu T)\omega ^2A^2=(1)/(2)* √(0.0031* 25)* 753.6^2* 0.0016^2=0.2023watt`

From the relation we can see that power
`P\ \propto\ A^2`

So if amplitude is halved then power will be
`(1)/(4)` times

So power will be equal to
`(0.2023)/(2)=0.0505watt`